(x-3)^2=(129-4)/5

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Solution for (x-3)^2=(129-4)/5 equation: 


x in (-oo:+oo)

(x-3)^2 = (129-4)/5 // - (129-4)/5

(x-3)^2-((129-4)/5) = 0

(x-3)^2-25 = 0

(x-3)^2-25 = 0

x^2-6*x-16 = 0

x^2-6*x-16 = 0

x^2-6*x-16 = 0

DELTA = (-6)^2-(-16*1*4)

DELTA = 100

DELTA > 0

x = (100^(1/2)+6)/(1*2) or x = (6-100^(1/2))/(1*2)

x = 8 or x = -2

(x+2)*(x-8) = 0

(x+2)*(x-8) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-8 )

x-8 = 0 // + 8

x = 8

x in { -2, 8 }

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